Statement of the Problem
I claim:
Given two points in a plane
and
, the distance
between them may be calculated as
.
I further claim that we may determine this starting from the area of a rectangle:
The
area of a rectangle with height
and
width
may be found with
.
The Plan Of Attack
- Use the rectangle area formula to derive a formula for the area of a square.
- Be rigorous!
- Define a square: A square is a rectangle with all four sides equal.
- So a square is a rectangle.
- So if the square has sides of length
,
the area of that rectangle with sides
and
is
.
- ... and, from that, a rule from the area of a square to the length of
each side.
- If we have the area of a square, we can solve
to
.
- Use the rectangle area formula for the area of a right triangle.
- Draw a right triangle with height
and width
.
- Duplicate it so that there is a rectangle with height
and width
.
- Since there are two triangles, and they must sum to the area of the
full rectangle
, the area
of each must be
.
- Use the above derivations to prove the Pythagorean Theorem:
Within
every right triangle whose legs are of length
and
and whose hypotenuse is of
length
, the lengths of the sides
will have the relationship
.
- Graded Classwork: Using the Internet or any other
resource, find a proof of the Pythagorean Theorem which you can understand
and explain. Write it in your own words and print it out or email it
to me at [email protected]
Sketch
a right triangle, label its sides
,
, and
,
and duplicate it four times, as in this illustration.
- Calculate the area of each right triangle
,
then multiply by four to determine the area of all four right triangles
together
.
- Calculate the area of the large square
.
- Subtract the area of the four triangles, leaving only the area of
the inner square
.
- Since the inner square has sides of length
,
its area is also
and, by
transitivity,
.
- Define the distance between two points
and
on the same axis (number line)
as
. So our only real
problem is to prove the distance between two points which are diagonal from
each other.
- This is just a definition. Explain it. Notice the absolute-value bars;
the distance between two points on a number line is always (positive
and) the same whichever way you look at the points because distance
does not have direction.
- (If they're curious, mention vectors, which have both distance and
direction.)
-
Construct
a right triangle using our diagonal points
and
, and a third
point
.
- Note that the orientation of this triangle may be different from in
this diagram. Is that a problem? No.
- Use the smaller distance formula (step 5) to determine the lengths of
both legs of this right triangle.
- The horizontal leg will have length
.
- The vertical leg will have length
.
- Use the Pythagorean theorem to determine the length of the hypotenuse
of this right triangle... which is the distance between our original two
points.
- Since this is a right triangle, the hypotenuse will have length
.
- Since we're squaring those inner terms, the absolute-value bars don't
matter any more:
.
- Demonstrate that the smaller distance formula works with this new distance
formula, so we need only use
regardless of where on the plane the points are.
Assessments
Proof-related questions:
Given
a parallelogram with measurements as shown, can you prove that its area
is still
?
Given
a triangle with measurements as shown, can you prove that its area is still
?
Given
a kite with diagonals
and
,
can you prove that its area is
?